Question

What is the molarity 10.0g of Cr(NO3)3 in 325 mL of solution

Answer 1

Step-by-step explanation:

molar mass Cr(NO3)3 = 238 g/mol

Convert 325 ml to liters: 325 mls x 1 L / 1000 mls = 0.325 L

Convert 10.0 g to moles: 10.0 g x 1 mol / 238 g = 0.0420 moles

Molarity = moles/liters = 0.0420 moles / 0.325 L = 0.129 M (3 sig. figs.)