Question

Find in standard form the equation of the line that is perpendicular to y=8x/3 +2 and passes through (-3, -6)

Answer 1

y =
`(-3)/(8)`x -
`(57)/(8)`

Explanation:

a perpendicular slope is the opposite reciprocal. The slope will be
`(-3)/(8)`

Two write the equation, you need the slope and the y-intercept. We have the slope (
`(-3)/(8)`). We know need to find the y-intercept.

We will use the m or slope of
`(-3)/(8)`, x value of -3 from the point (-3,-6)and the y value of -6 from the point (-3,-6)

y = mx + b

-6 =
`(-3)/(8)`(
`(-3)/(1))`) + b

-6 =
`(9)/(8)` + b Subtract
`(9)/(8)` from both sides

`(-6)/(1 )` -
`(9)/(8)` =
`(9)/(8)` -
`(9)/(8)` + b Use the common denominator of 8

`(-48)/(8)` -
`(9)/(8)` = b

`(-57)/(8)` = b

y =
`(-3)/(8)`x -
`(57)/(8)`