menu
Qamnty
Login
Register
My account
Edit my Profile
Private messages
My favorites
Helpp You have one type of chocolate that sells for $2.70/lb and another type of chocolate that sells for $5.10/lb. You would like to have 16.8 lbs of a chocolate mixture that s…
Ask a Question
Questions
Unanswered
Tags
Ask a Question
Helpp You have one type of chocolate that sells for $2.70/lb and another type of chocolate that sells for $5.10/lb. You would like to have 16.8 lbs of a chocolate mixture that s…
asked
Dec 19, 2024
22.4k
views
4
votes
Helpp
You have one type of chocolate that sells for $2.70/lb and another type of chocolate that sells for $5.10/lb. You would like to have 16.8 lbs of a chocolate mixture that sells for $3.30/lb. How much of each chocolate will you need to obtain the desired mixture?
You will need
--------- lbs of the cheaper chocolate
and
-----------lbs of the expensive chocolate.
Mathematics
college
Kevinstueber
asked
by
Kevinstueber
8.5k
points
answer
comment
share this
share
0 Comments
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
1
Answer
6
votes
Answer:
12.6 lbs of cheaper chocolate
4.2 lbs of expensive chocolate
Stephen Gross
answered
Dec 24, 2024
by
Stephen Gross
7.7k
points
ask related question
comment
share this
0 Comments
Please
log in
or
register
to add a comment.
← Prev Question
Next Question →
No related questions found
Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.
Categories
All categories
Mathematics
(3.7m)
History
(955k)
English
(903k)
Biology
(716k)
Chemistry
(440k)
Physics
(405k)
Social Studies
(564k)
Advanced Placement
(27.5k)
SAT
(19.1k)
Geography
(146k)
Health
(283k)
Arts
(107k)
Business
(468k)
Computers & Tech
(195k)
French
(33.9k)
German
(4.9k)
Spanish
(174k)
Medicine
(125k)
Law
(53.4k)
Engineering
(74.2k)
Other Questions
How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
A bathtub is being filled with water. After 3 minutes 4/5 of the tub is full. Assuming the rate is constant, how much longer will it take to fill the tub?
Twitter
WhatsApp
Facebook
Reddit
LinkedIn
Email
Link Copied!
Copy
Search Qamnty