Question

Find two positive numbers whose square have a sum of 34 and difference of 16

Answer 1

Answer: 3, 5

Explanation:

Let x be one of the numbers and y be the other number

x²+y²=34 add the to equations to eliminate the y

x²-y²=16

2x² = 18

x²=9

x=√9

x=3 plug into equation to find y

x²+y²=34

3²+y²=34

9+y²=34

y²=25

y=√25

y=5

Answer 2

3 and 5

Explanation:

3^2+5^2

9+25=34

25-9=16