Explanation:
Since they are both equations for 'y' ...you can just equate and solve
x^2 + 19x + 49 = 5x + 4 subtract 5x + 4 from both sides
x^2 + 14x + 45 = 0 Use quadratic formula
with a = 1 b= 14 c = 45
to find the two 'x' coordinates -5 and -9
Use these values in either equation to calculate
the 'y' coordinates : -21 and -41
(-5,-21) and ( -9, -41)
Here is a graph for verification: