Question

A test charge has a force of 0.137 N on it when it is placed in an electric field intensity of 3.87x10^5 N/C. What is the magnitude of the charge?

Answer 1

3.54 x 10^-7 coulombs

Step-by-step explanation:

The magnitude of the charge can be determined using the formula:

Electric field intensity (E) = Force (F) / Charge (q)

Rearranging the formula, we get:

Charge (q) = Force (F) / Electric field intensity (E)

Substituting the given values, we get:

Charge (q) = 0.137 N / (3.87 x 10^5 N/C)

q = 3.54 x 10^-7 C

Therefore, the magnitude of the charge is 3.54 x 10^-7 coulombs.