Question

A body of mass 1500g is dropped from 20m high tower. It will reach the ground in how many seconds? Step-by-Step explanation.

Answer 1

Answer: 2.02 seconds.

Explanation: Let’s solve this problem step-by-step. When an object is dropped from a height, it falls freely under the influence of gravity. The distance fallen by a freely falling object is given by the equation of motion: s = 1/2 * g * t^2, where s is the distance fallen, g is the acceleration due to gravity (9.8 m/s^2 on Earth), and t is the time taken to fall that distance.

In this case, the body of mass 1500g (which is irrelevant to the problem) is dropped from a height of 20m. So we can plug s = 20m and g = 9.8 m/s^2 into the equation above to find the time taken for the body to reach the ground: 20 = 1/2 * 9.8 * t^2. Solving for t, we get t^2 = 20 / (1/2 * 9.8) = 4.08. Taking the square root of both sides, we get t = sqrt(4.08) ≈ 2.02 seconds.

So, a body of mass 1500g dropped from a 20m high tower will reach the ground in approximately 2.02 seconds.

Answer 2

h = (1/2) * g * t^2


h = height of the tower (20m)

g = acceleration due to gravity (9.8 m/s^2)

t = time taken to reach the ground (unknown)

t = sqrt(2h/g)

Plugging in the values for h and g, we get:

t = sqrt(2(20)/9.8)

Evaluating this expression, we get:

t = 2.02 seconds

Therefore, the body will reach the ground in approximately 2.02 seconds ion i hope that helped lol