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Find the inverse of the function on the given domain.

f(x) = (x-12)^2,[12,infinity)
f^-1(x)=

1 Answer

2 votes

Answer:

To find the inverse of the function f(x) = (x - 12)^2 on the domain [12, infinity), we can follow the steps below:

Step 1: Replace f(x) with y.

y = (x - 12)^2

Step 2: Swap the positions of x and y.

x = (y - 12)^2

Step 3: Solve for y.

Taking the square root of both sides, we get:

y - 12 = ±√x

Adding 12 to both sides, we get:

y = 12 ± √x

However, we are given that the domain of the inverse function is [12, infinity). Since the expression 12 - √x is negative for x > 144, we must choose the positive square root to satisfy the given domain. Therefore, the inverse function is:

f^-1(x) = 12 + √x, x ≥ 144

Note that we have restricted the domain of the inverse function to [144, infinity) to ensure that the function is one-to-one and has a unique inverse.

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User Hintham
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