Answer: the ball reaches a maximum height of 76 ft, and it takes 2 seconds to reach the highest point.
Step-by-step explanation: The acceleration induced by gravity is estimated to be approximately -32 ft/s^2, with the negative value indicating its downward direction.
At the apogee of the ball's trajectory, its vertical velocity experiences a momentary cessation.
The duration required for the ball to attain its maximum height can be determined through employment of the equation t = Vf / a, in which Vf denotes the attained final velocity (which is zero in the present scenario) and a denotes the gravitational acceleration. Upon substitution of the given numerical values, the resulting value of t is determined to be equal to 2 seconds, achieved through the utilization of the equation t = 64 / 32.
The determination of the maximum height achieved by the ball can be achieved through utilization of the formula h = hi + Vit + 1/2at^2, with hi denoting the initial height (12 ft), Vi representing the initial velocity (64 ft/s), a signifying the acceleration due to gravity (-32 ft/s^2), and t representing the time it takes for the ball to reach the apex of its trajectory (2 seconds). Upon entering the provided numerical values into the formula, the resulting value for the height of the object can be determined as h = 12 + 64(2) + 1/2(-32)(2)^2, which equates to 76 feet.