Question

What is the area of right triangle 0,0 4,3 -2,11

Answer 1

25 units²

Explanation:

Area of a triangle = (1/2)b*h

After graphing the triangle you can see that the two legs are at points

(4,3) and (-2,11) and (4,3) and (0,0). Using the distance formula:

`\sqrt{(x_(2)-x_(1))^(2) + (y_(2)-y_(1))^(2)}`

then plug in the first line

`\sqrt{(-2-4)^(2) + (11-3})^(2)}`

simplify

`\sqrt{(-6)^(2) + (8})^(2)}`

`√(36 +64)`

`√(100)`

10

then the second line

`\sqrt{(4-0)^(2) + (3-0)^(2)}`

`\sqrt{(4)^(2) + (3)^(2)}`

`√(16 + 9)`

`√(25\\)`

=5

5*10=50

50*0.5 =25

so the area is equal to 25 units²