The given radioactive decay formula is:
y = ab^x
where,
y = final amount
a = initial amount
b = decay factor
x = number of half-lives elapsed
Here, the initial amount (a) is given as 2,000 grams of Flerovium-289, and the half-life (t1/2) is 30 seconds.
To find the decay factor (b), we can use the formula:
b = 1/2^(t/t1/2)
where, t is the time elapsed. Here, t = 5 minutes = 300 seconds.
b = 1/2^(300/30) = 1/2^10 = 1/1024
Now, we can find the final amount (y) after 5 minutes by using the formula:
y = ab^x
where, x is the number of half-lives elapsed in 5 minutes.
x = t/t1/2 = 300/30 = 10
y = 2,000 * (1/1024)^10
y ≈ 1.95 grams (approx)
Therefore, the answer is option (b) 1.95 grams.