Question

a zero order reaction has a rate constant of 0.112ms. if the initial concentration of the reaction is 2.50 m, what is the half-life of the reactant? remember to report your answer with the correct number of significant figures.

Answer 1

The half-life of a zero-order reaction can be found using the formula: t1/2 = [A]0 / (2k). In this case, the rate constant is 0.112 ms and the initial concentration is 2.50 M. The half-life is approximately 11 ms.

Step-by-step explanation:

The half-life of a zero-order reaction can be found using the formula:

t1/2 = [A]0 / (2k)

Where t1/2 is the half-life, [A]0 is the initial concentration of the reactant, and k is the rate constant. In this case, the rate constant is given as 0.112 ms and the initial concentration is 2.50 M. Plugging in these values, we have:

t1/2 = 2.50 M / (2 * 0.112 ms)

t1/2 = 11.16 ms

Round the answer to the correct number of significant figures:

t1/2 ≈ 11 ms