Question

A 8m 40 cm high vertical pole casts a shadow 5m 60 cm. Find at the same time, the length of the shadow cast by another pole 6m high.

Answer 1

4m

Explanation:

Simple ratio.

840/560=600/x (Simplify)

3/2=600/x (Cross-multiply)

3x=1200

x=1200/3=400cm=4m

Answer 2

`\huge\bold{Solutìon}`

Let x m Be the length of shadow whose pole is 6 m .

Now,

According to the information,

Representing these information in tabular form

`{ \begin{gathered} \star\begin{gathered}\begin{gathered}\begin{array} \\ \rm \: height \: of \: pole\:&\rm \: 8.40&\rm 6\: \: \\ \\ \rm length \: of \: its \: shadow &\rm 5.60&\rm x \\ \end{array} \\ \\\end{gathered}\end{gathered} \end{gathered} }`

Now,

Clearly height of pole and shadow are in direct variation together so this are direct variation.

Now, According to the concept of Direct variation we solve this question

`\displaystyle \large \sf \: { \leadsto \: \: \: \: (8.40)/(5.60) } = \: \: (6)/(x)`

`\displaystyle \large \sf \: { \leadsto \: 8.40x = 6 * 5.60}`

`\displaystyle \large \sf \: { \leadsto{ \: \: x \: = (6 * 5.60)/(8.40) }}`

`\displaystyle \large \sf \: { \leadsto \: x \: = (33.6)/(8.4) }`

`\displaystyle \large \bf \: { \leadsto \: x \: = 4}`

Final answer

• x = 4

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