Question

Find the distance between the point (2,1) and the line 3x- 4y+15=0​

Answer 1

Correct answers 5.4

Distance from point (2,3) to the line 3x+4y+9=0

=>r=

3

2

+4

2

∣3(2)+4(3)+9∣

=>r=

9+16

∣16+12+9∣

=>r=

5

27

=>r=5.4

Answer 2

Explanation:

3

x

−

4

y

+

15

=

0

.

y

=

3

4

x

−

1

2