asked 187k views
5 votes
When flying out of a place your expected to fly to 1500 feet before leaving the airspace in a pilots plane their distance measuring equipment says they have traveled 2 miles before they reached this altitude what angle was the pilot flying as they took off from the runway?

asked
User Ibamboo
by
8.2k points

1 Answer

5 votes

Answer: To solve this problem, we can use trigonometry and the relationship between angle, distance, and altitude in a right triangle.

Let's denote the angle the pilot was flying at takeoff as θ. We can then use the tangent function to find θ, since:

tan(θ) = opposite/adjacent

In this case, the opposite side is the altitude the pilot reached (1500 feet), and the adjacent side is the distance the pilot traveled before reaching that altitude (2 miles = 10560 feet). So we can plug in these values and solve for θ:

tan(θ) = 1500/10560

θ = tan⁻¹(1500/10560)

θ ≈ 7.67 degrees

So the pilot was flying at an angle of approximately 7.67 degrees at takeoff from the runway.

Explanation:

answered
User Nur Zico
by
7.5k points
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