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How many atoms are present in 3.14 g of copper (Cay?​

1 Answer

5 votes

Answer:

2.98 × 10^22 atoms

Step-by-step explanation:

To determine the number of atoms in 3.14 g of copper, we need to use the atomic mass of copper and Avogadro's number.

The atomic mass of copper (Cu) is 63.55 g/mol, which means that one mole of copper atoms has a mass of 63.55 g. Avogadro's number, which represents the number of particles (atoms or molecules) in one mole of a substance, is 6.022 × 10^23 particles/mol.

Using these values, we can first calculate the number of moles of copper in 3.14 g:

moles of Cu = mass of Cu / atomic mass of Cu

moles of Cu = 3.14 g / 63.55 g/mol

moles of Cu = 0.0495 mol

Then, we can calculate the number of atoms in 0.0495 mol of copper:

number of atoms = moles of Cu × Avogadro's number

number of atoms = 0.0495 mol × 6.022 × 10^23 atoms/mol

number of atoms = 2.98 × 10^22 atoms

Therefore, there are approximately 2.98 × 10^22 atoms in 3.14 g of copper.

answered
User Thao Ngo
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