Question

Find the equation of a parallel to y=-3x-5 that passes through the point (2,-1)

A) y-1= -1/3 (x-2)
B)y+1=-1/3(x+2)
C)y-1=-3(x+2)
D)y+1=-3(x-2)

Answer 1

Answer:

D: y + 1 = -3(x - 2).

Explanation:

The slope of the line y = -3x - 5 is -3, since it is in the form y = mx + b, where m is the slope.

A line parallel to this line will have the same slope, -3. Using the point-slope form of a linear equation, we can find the equation of the line:

y - y1 = m(x - x1), where (x1, y1) is the given point.

Plugging in the values, we get:

y - (-1) = -3(x - 2)

Simplifying and rearranging, we get:

y + 1 = -3x + 6

Subtracting 1 from both sides, we get:

y = -3x + 5

Therefore, the answer is option D: y + 1 = -3(x - 2).