asked 92.3k views
3 votes
In STU, t = 34 cm, u = 16 cm and _S=56°. Find the length of s, to the nearest centimeter.

1 Answer

2 votes

28

Explanation:

a^2=b^2+c^2-2bc\cos A

a

2

=b

2

+c

2

−2bccosA

From reference sheet.

s^2 = 34^2+16^2-2(34)(16)\cos 56

s

2

=34

2

+16

2

−2(34)(16)cos56

Plug in values.

s^2 = 1156+256-2(34)(16)(0.559193)

s

2

=1156+256−2(34)(16)(0.559193)

Square and find cosine.

s^2 = 1156+256-608.40188

s

2

=1156+256−608.40188

Multiply.

s^2 = 803.59812

s

2

=803.59812

Add.

s=\sqrt{803.59812} \approx28.348 \approx28

s=

803.59812

≈28.348≈28

answered
User Garbagecollector
by
8.2k points

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