Question

Kim and Julio go to a raceway to watch Julio's older brother, Raul, compete. Raul's car

covers the 2.5 km in 12 seconds, reaching a speed of 180 km/h. Use the equation below
to determine the rate of acceleration of Raul's car.
In this equation, a is acceleration, v is the final velocity, v; is the initial velocity, and
t is time. (Hint: The initial velocity is 0 km/h.)
What is the acceleration of Raul's car?
a =
(Vy-vi)
t

Answer 1

The acceleration of Raul's car is calculated using the formula a = (v - vi) / t, where v is the final velocity and vi is the initial velocity. After converting 180 km/h to 50 m/s, the calculation yields an acceleration of approximately 4.17 m/s².

Step-by-step explanation:

To determine the acceleration of Raul's car, we can use the formula given: a = (v - vi) / t. Here, v is the final velocity, vi is the initial velocity, and t is the time. Given that the initial velocity (vi) is 0 km/h and the final velocity (v) is 180 km/h, we need to convert the final velocity to meters per second (m/s) because acceleration is typically expressed in meters per second squared (m/s²). To convert km/h to m/s, we use the conversion factor: 1 km/h = 1/3.6 m/s.

First, convert 180 km/h to m/s:
180 km/h = 180 / 3.6 m/s = 50 m/s.

Now, we can calculate the acceleration:
a = (v - vi) / t
a = (50 m/s - 0 m/s) / 12 s
a = 50 m/s / 12 s
a ≈ 4.17 m/s².

The acceleration of Raul's car is approximately 4.17 m/s².

Answer 2

Step-by-step explanation:

U=0

V=180 km/h

T=12 sec

A=(v-u)÷t

=(180-0)÷12

=180÷12

=15km/h

Hence, the acceleration of the car is 15km/h