Answer is in the graph (3, 1) is the solution
Step by step
EQ #1 y = 2x - 5
Create a table, using the equation to find Y
When x =0, y = 2( 0) -5, y= -5
When x = 1, y= 2( 1) -5, y= -3
Continue with the remaining x values
Graph these points
X. Y
0 -5
1 -3
2 -1
3 1
4 3
EQ # 2 y = -x + 4
Create a table, using the equation to find Y
When x =0, y = -1(0) +4, y= 4
When x = 1, y = -1 (1 ) + 4, y= 3
Continue with the remaining x values
Graph these points
X. Y
0 4
1 3
2 2
3 1
4 0
The solution of the two equations is where the two lines meet. ( 3, 1)