Question

Equations with Fractions

Can someone please show me how to work this question out. Im really stuck. Thanks.

Answer 1

`\cfrac{1}{2}(1-x)-\cfrac{1}{3}(2+x)+\cfrac{1}{4}(3-x)=1 \\\\\\ \stackrel{\textit{multiplying both sides by }\stackrel{LCD}{12}}{12\left( \cfrac{1}{2}(1-x)-\cfrac{1}{3}(2+x)+\cfrac{1}{4}(3-x) \right)~~ = ~~12(1)} \\\\\\ 6(1-x)-4(2+x)+3(3-x)=12\implies 6-6x-8-4x+9-3x=12 \\\\\\ 7-13x=12\implies 7=13x+12\implies -5=13x\implies \cfrac{-5}{13}=x`

Answer 2

First eliminate the fractions by multiplying each term by the LCM of 2,3 and 4, which is 12,
So doing this gives
6(1-x) - 4(2+x)+3(3-x) =