Question

The length of a rectangle is 2 in longer than its width. If the perimeter of the rectangle is 36 in, find its area. (please hurry) ​

Answer 1

length = 10 in

width = 8 in

Explanation:

Perimeter of a rectangle = 2(length + width)

Then:

36 = 2(h + w) Eq. 1

h = 2 + w Eq. 2

h = length

w = width

From Eq. 1

36/2 = h + w

18 = h + w Eq. 3

Replacing Eq. 2 in Eq. 3

18 = (2+w) + w

18 = 2 + 2w

18 - 2 = 2w

16 = 2w

16/2 = w

w = 8

From Eq. 2

h = 2 + w

h = 2 + 8

h = 10

Check:

from Eq. 1:

36 = 2(h + w)

36 = 2(10 + 8)

36 = 2*18

Answer 2

The answer to the question is: