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A ladder is placed against a building forming an angle of elevation of 52. If it reaches the building 12 feet above the ground, how far is the foot of the ladder from the building?

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We can use trigonometry to solve this problem. Let x be the distance from the foot of the ladder to the building, and let y be the length of the ladder. Then, we have:

tan(52) = y/x (since tangent = opposite/adjacent, and y is opposite to the angle of elevation and x is adjacent)

We also know that the ladder reaches 12 feet above the ground, so we have:

y = 12 + x (since y is the hypotenuse of the right triangle formed by the ladder, the ground, and the building)

We can substitute the second equation into the first to get:

tan(52) = (12 + x)/x

Simplifying this equation, we get:

tan(52)x = 12 + x

Using a calculator to find the tangent of 52, we get:

1.2799x = 12 + x

Solving for x, we get:

0.2799x = 12

x = 42.87 feet (rounded to two decimal places)

Therefore, the foot of the ladder is approximately 42.87 feet away from the building.

answered
User Ramesh Soni
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