Question

Suppose that y is directly proportional to x and inversely proportional to the square of z. If x=48 when y=8 and z=3, find x when y=12 and z=2?

Answer 1

x = 48

Explanation:

First you find k

y =
`(xk)/(z)`

8 =
`(48k)/(3)` Multiply both sides by
`(3)/(48)`

(8)
`(3)/(48)` =
`(48x)/(3)`
`((3)/(48))`

0.5 = k

y =
`(xk)/(z)`

12 =
`(x.5)/(2)` Multiply both sides by
`(2)/(.5)`

(12)
`(2)/(.5)` =
`(x.5)/(2)`
`((2)/(.5))`

48 = x

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