Question

what is the final volume of a gas that initially occupies 2.50 L at 298 K and is subsequently heated to 321 k ?

Answer 1

2.69 L

Step-by-step explanation:

Volume is directly proportional to temperature, so we can use the following formula:

`(V1)/(T1) = (V2)/(T2)`

V₁ = 2.50 L

T₁ = 298 K

T₂ = 321 K

If we plugin the following values we end up with the equation:

`(2.50L)/(298K) = (V2)/(321K)`

If we solve for V₂ using a calculator we end up with V₂ ≈ 2.69 L