Question

Determine the empirical formula for a compound that is composed of 0.953 mol Na, 0.322 mol Al, and 1.93 mol F.

Answer 1

Answer: NaAlF6

Step-by-step explanation:

1) divide by the smallest number of moles

0.953/.322 =2.96 round to 3 Na

.322/.322 = 1 Al

1.93/.322 =5.99 round to 6 F

2) write in order numbers were give

NaAlF6