Question

Please help, just need H!

Answer 1

Explanation:

`f(x)=(27)/(4) x`

`p(x)=√(3x)`

`[p(x)]^6=(3^(1)/(2)x^(1)/(2))^6= 27x^3`

`[p(x)]^6g(x)=27x^3((x)/(4) )=(27x^4)/(4)`

`[p(x)]^6g(x)[t(x)]^3=(27x^4)/(4) ((1)/(x) )^3=(27x^4)/(4x^3) =(27)/(4) x`

Solution:
`[p(x)]^6g(x)[t(x)]^3=f(x)`

I think there might be nicer solutions but this works!