How many all.number of possible.diagonal that drawing in differnt verticle of nonagon

Question

asked Jul 17, 2024 45.2k views

1 Answer

Chiseled · Answer 1 · 2024-07-22T23:31:13+0000

It sounds like you want to find how many diagonals a nonagon has.

A nonagon has n = 9 sides.

The number of diagonals would be...

$d = \text{number of diagonals}\\\\d = (n(n-3))/(2)\\\\d = (9(9-3))/(2)\\\\d = (9(6))/(2)\\\\d = (54)/(2)\\\\d = 27\\\\$

A nonagon has 27 different diagonals.