Question

A submarine travels 12 km due West from its base and then turns and travels due South for 14.8 km. How far away is the submarine from its base? .

Answer 1

The answer is 19.1

Explanation:

`z = \sqrt{ {x}^(2) + {y}^(2) } = \sqrt{ {12}^(2) + {14.8}^(2) } = 19.1`

Answer 2

the submarine travels 26.8 km. from its base