Question

B

LM is the midsegment of trapezoid ABCD. AB = 2x+8, LM = 4x+4, DC = 156. What is the value of x?
(2 points)
X =

Answer 1

x = 26

Explanation:

the midsegment of a trapezoid is calculated as

• half the sum of the parallel bases

LM =
`(AB+DC)/(2)` ( substitute values )

4x + 4 =
`(2x+8+156)/(2)` =
`(2x+164)/(2)` = x + 82 ( subtract x from both sides )

3x + 4 = 82 ( subtract 4 from both sides )

3x = 78 ( divide both sides by 3 )

x = 26