Final answer:
The given DNA strand is transcribed to mRNA, and then translated to a protein sequence, with mRNA codons corresponding to specific amino acids. The transcription results in an amino acid sequence starting with Met-Val and ending with a stop codon (*).
Step-by-step explanation:
To transcribe and translate the given DNA strand, we first need to understand that during transcription, the DNA sequence is copied into mRNA, which is then used as a template for translation to build a protein. For transcription, adenine (A) pairs with uracil (U) in RNA instead of thymine (T), cytosine (C) pairs with guanine (G), guanine (G) pairs with cytosine (C), and thymine (T) pairs with adenine (A).
Given DNA Strand: 5'-GTC CTT TAC CAT CGA TTG GAA AAC GTT AAA ATC CAG TTC CAT-3'
Transcription:
The transcribed mRNA sequence would be 5'-CAG GAA AUG GUA GCU AAC CUU UUG CAA UUU UAG GUC AAG GUA-3'
Translation:
During translation, the mRNA sequence is read in codons, starting from the AUG start codon. Each triplet codon corresponds to a specific amino acid. Using the codon lookup table, we can translate the codons until a stop codon is reached.
The translated amino acid sequence (from the start codon AUG to a hypothetical stop codon) would be: N-Met-Val-Ala-Asn-Leu-Leu-Gln-Phe-*-C