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If angle ABC is equilateral find the value of c and y if side AB =7y 19 and Side BC =11y-89 and angle c is 8x-44

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Final answer:

In an equilateral triangle with sides 7y + 19 and 11y - 89, the value of y is determined to be 27. Substituting y, the length of side c is calculated to be 208. Since all angles in an equilateral triangle are 60 degrees, the angle expression 8x - 44 equals 60, yielding x as 13.

Step-by-step explanation:

Finding Values of c and y in an Equilateral Triangle

In an equilateral triangle, all sides have the same length and all angles are equal. This means that each angle has a measure of 60 degrees. If we have an equilateral triangle ABC with sides AB and BC, given as AB = 7y + 19 and BC = 11y - 89, we can find the value of y by equating these expressions, since they represent the lengths of the sides in an equilateral triangle.

Therefore, we can write the equation:

  • 7y + 19 = 11y - 89

By solving this equation, we can find the value of y. Moving the y terms to one side and the constants to the other, we get:

  • 7y - 11y = -89 - 19
  • -4y = -108
  • y = 27

Now, to find the value of c, we can substitute y into one of the side expressions:

  • c = 7y + 19
  • c = 7(27) + 19
  • c = 189 + 19
  • c = 208

For the angle C, or angle c as mentioned in the question, which is given by 8x - 44, we know that in an equilateral triangle, all angles are 60 degrees. Therefore,

  • 8x - 44 = 60
  • 8x = 104
  • x = 13

With these calculations, we have found that the value of y is 27, the length c is 208, and the value of x is 13.

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User DdoGas
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