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Calcium-47 is a β− emitter with a half-life of 4.50 days.If a bone sample contains 2.34g of this isotope, at what rate will it decay?

Express your answer in becquerel.

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Final answer:

To find the decay rate of Calcium-47, you calculate the decay constant using its half-life and use it along with the sample's mass to determine the number of decaying nuclei per second, which gives you the activity in becquerels.

Step-by-step explanation:

To calculate the decay rate of Calcium-47, which is a β− emitter with a half-life of 4.50 days, we will use the formula that relates the decay constant (λ) to the half-life (t₁/₂): λ = ln(2)/t₁/₂. First, we find the decay constant by substituting the half-life value into the equation.

λ = ln(2)/4.50 days = 0.1541 days⁻¹

Next, to find the number of decays per second (activity in becquerels), we will use the formula A = λN, where N is the number of unstable nuclei in the sample. To calculate N, we need the mass of the isotope and its molar mass (which is approximately 47 g/mol for Calcium-47).

N = (mass of isotope in grams / molar mass) × Avogadro's number

N = (2.34g / 47 g/mol) × 6.022×10¹¹ nuclei/mol

This gives us the number of nuclei. We then calculate the activity:

A = λN = 0.1541 days⁻¹ × N nuclei

This calculation will yield the decay rate of Calcium-47 in the bone sample in becquerels.

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