Final answer:
The change in volume of water in Stewart's tank due to a leak over a minute can be represented by the equation V_new = V - (x/1), where x is the rate of leakage per minute and V is the initial water volume.
Step-by-step explanation:
To determine the change in volume of water from Stewart's tank due to a leak over a minute, we need to know the rate at which the water is leaking. However, since the exact leak rate isn't provided, we can work through an example using a hypothetical leak rate.
Let's say that the water tank leaks at a rate of x liters per minute. The change in water volume in the tank after 1 minute can then be represented by the complex fraction -x/1, since the volume decreases.
If we know the initial volume of the water in the tank, we subtract the leaked volume to find the new volume after one minute. For example, if the initial volume is V liters and the leak rate is x liters per minute, the new volume Vnew after 1 minute is:
Vnew = V - (x/1)
This simple equation demonstrates the change in water volume due to the leak over the specified time frame. Complex fractions often involve ratios and division, but in this context, since the rate is per minute, we are simply subtracting the leaked amount directly from the initial volume.
Let's say the change in volume of water in 1 minute is represented by 'x' liters. The time taken is 1 minute, which can be expressed as 1/1 minute. Therefore, the complex fraction would be (x liters) / (1/1 minute).
Keep in mind that the actual value of 'x' would depend on the specific situation and cannot be determined without additional information.