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CAN SOMEONE HELP ME PLEASE

CAN SOMEONE HELP ME PLEASE
asked 15.1k views
10 votes
CAN SOMEONE HELP ME PLEASE

CAN SOMEONE HELP ME PLEASE-example-1
asked
User LMS
by
7.8k points

1 Answer

6 votes

Answer:


(√(189x^3y^6) )/(√(3x) ) \\= (√(3^2(7)(3)(x^2)(x)(y^3)^2) )/(√(3x) ) \\=\sqrt{((3xy^3)^2(7)(3x))/(3x) }\\=3xy^3√(7)

answered
User Dmitriy Kovalenko
by
8.6k points
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