Question

Which XXX causes every character in string x to be output?

for (XXX) {
System.out.println(x.charAt(i));
}

a. i = 0; i <= x.length(); ++i
b. i = 0; i < x.length(); ++i
c. i = 0; i < (x.length() + 1); ++i
d. i = 0; i < (x.length() - 1); ++i

Answer 1

The correct loop condition for outputting every character in string x is 'i = 0; i < x.length(); ++i', as it will iterate over all valid indices of the string.

Step-by-step explanation:

The question is asking about a loop condition that will cause every character in a string variable x to be output using a loop and System.out.println. The correct answer is option b, i = 0; i < x.length(); ++i. This is because string indices in Java start at 0 and go up to but do not include x.length(). The loop initializes i to 0, and iterates as long as i is less than x.length(), incrementing i by 1 each time through the loop. This ensures that all characters in the string from index 0 to x.length() - 1 are printed.