Question

Can someone please help me with the problem? I have the answer but I need the step by step explanation for it.

Directions: Find the roots of the equations.

-2x^2-3x-9

Answer: {3+3i√7/-4, 3-3i√7/-4}​

Answer 1

{3+3i√7/-4, 3-3i√7/-4}​ is in fact correct, here is the explanation

Explanation:

By replacing y with 0 in
`y=-2x^2-3x-9`, you can use the quadratic formula
`\frac{b+(or -)\sqrt{b^(2) -4ac} }{2a}` and plug in the values a = -2, b = -3, and c = -9 to end up with your answer. If you are confused as to i showed up, it is because in the equation, the discriminant is 9 + 8 * -9 or -63. if the discriminant is a negative number, there will be no real solutions, and only imaginary ones.