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When the following equation is balanced, what is the coefficient of B₂O₃?

B₅H₉(l) + O₂(g) => B₂O₃(s) + H₂O(g)

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User Rema
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1 Answer

2 votes

Final answer:

The coefficient of B₂O₃ when balancing the equation B₅H₉(l) + O₂(g) ⇒ B₂O₃(s) + H₂O(g) is 5. This coefficient reflects the molar amount of B₂O₃ resulting from a balanced chemical equation.

Step-by-step explanation:

When the equation B₅H₉(l) + O₂(g) ⇒ B₂O₃(s) + H₂O(g) is balanced, the coefficient of B₂O₃ is 5. This coefficient indicates the molar quantity of B₂O₃ in the balanced equation. To balance the equation, one must ensure that there is the same number of atoms of each element on both sides of the reaction.

Balancing chemical reactions involves using the lowest whole-number coefficients to maintain the law of conservation of mass. In this case, balancing the boron and oxygen atoms will lead you to determine the correct stoichiometry for both reactants and products, ensuring a balanced chemical equation.

answered
User Tran Triet
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8.5k points
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