Question

State whether it is infinite loop, finite loop, no loop at all, or compiler error.

int x = 0; while (x<0) { cout << 0; x++; }
A. Infinite loop
B. Finite loop
C. No loop at all
D. Compiler error

Answer 1

The code will result in no loop at all because the condition for the while loop to execute is not satisfied initially (x is not less than 0). There is no syntax error, hence no compiler error, and it is not an infinite loop.

Step-by-step explanation:

The code snippet provided is to be analyzed to determine the type of loop it represents. Given the initial condition x = 0 and the while loop condition x < 0, the loop body will not execute because the initial condition does not satisfy the loop's condition. Therefore, no iterations will occur. This leads us to the conclusion that this is C. No loop at all, because the loop's condition is never true from the start. There is no compiler error in the syntax, and it is not an infinite loop because the condition to enter the loop is not met.