Final answer:
To produce 0.56 grams of quick lime, 1.0 gram of limestone, which is primarily composed of calcium carbonate (CaCO3), must be heated.
Step-by-step explanation:
The student asked how many grams of limestone should be heated to form 0.56 grams of quick lime. Limestone is primarily composed of calcium carbonate (CaCO3), which when heated decomposes into calcium oxide (CaO, or quick lime) and carbon dioxide (CO2). The chemical equation for this process is:
CaCO3(s) → CaO(s) + CO2(g)
From Example 3.7.1 we know that heating 10.0 grams of calcium carbonate produces 5.6 grams of calcium oxide. Therefore, the ratio of calcium carbonate to calcium oxide by mass is 10.0 g to 5.6 g. To find out how much limestone is needed to produce 0.56 grams of quick lime, we can set up a direct proportion:
(10.0 g CaCO3) / (5.6 g CaO) = (x g CaCO3) / (0.56 g CaO)
Cross-multiply and solve for x:
x = (10.0 g CaCO3 × 0.56 g CaO) / (5.6 g CaO)
x = (10.0 × 0.56) / 5.6
x = 1.0 g
Therefore, 1.0 gram of calcium carbonate must be heated to produce 0.56 grams of quick lime.