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Bryce and Sydney are traveling towards each other from points that are 156 miles apart. If Sydney is traveling 10 mph faster than and they meet after 3 hours, how fast was each traveling?

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User Aruni
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1 Answer

4 votes

Final answer:

Bryce was traveling at 21 mph, and Sydney was traveling at 31 mph, with Bryce's speed determined by solving the equation 3x + 3(x + 10) = 156, where x is Bryce's speed in mph.

Step-by-step explanation:

Bryce and Sydney are 156 miles apart and are traveling towards each other. Sydney travels 10 mph faster than Bryce and they meet after 3 hours. To determine how fast each was traveling, let's define Bryce's speed as x mph and Sydney's as x + 10 mph. Since they meet after 3 hours, the combined distance they cover will equal 156 miles. The equation to represent this situation is:

3x + 3(x + 10) = 156

Solving for x, we add the terms involving x:

3x + 3x + 30 = 156

Combine like terms:

6x + 30 = 156

Subtract 30 from both sides:

6x = 126

Divide by 6:

x = 21

Now we know Bryce was traveling at 21 mph and Sydney was traveling at 31 mph since she was moving 10 mph faster than Bryce.

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User Bkqc
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