Final answer:
The DNA coding strand is sequence b) 5'-ACTTGCCATA-3', the DNA template strand is sequence c) 3'-TGAACGGTAT-5', and the resulting mRNA is sequence a) 5'-ACUUGCCAU-3'. The coding strand shares the same sequence as the mRNA but has T instead of U, and the template strand is complementary to both the coding strand and the resulting mRNA.
Step-by-step explanation:
The question relates to the concepts of transcription and translation in molecular biology which are the processes through which DNA sequences are used to produce RNA and proteins, respectively.
Initially, we need to identify the DNA coding strand, the DNA template strand, and the resulting mRNA sequence. DNA sequences come in pairs of strands: the coding strand and the template strand.
The coding strand is the DNA sequence that has the same sequence as the mRNA, but with thymine (T) instead of uracil (U).
On the other hand, the template strand is used during transcription to make mRNA and its base pairs are complementary to both the coding strand and the resulting mRNA.
Identifying Sequences:
- Sequence a) 5'-ACUUGCCAU-3': This is an RNA sequence (because it contains uracils) and, therefore, it is the resulting mRNA sequence.
- Sequence b) 5'-ACTTGCCATA-3': This sequence contains thymine and is the DNA coding strand. It's the DNA coding strand because it has thymines (T) instead of uracils (U).
- Sequence c) 3'-TGAACGGTAT-5': This is the DNA template strand; it is complementary to the DNA coding strand and is oriented in the 3' to 5' direction which is the correct orientation for the template strand during transcription.
The complementarity rules dictate that A pairs with T (U in RNA), and C pairs with G. Therefore, the mRNA sequence is complementary to the template strand (with uracil replacing thymine).