Question

Write a reaction that shows what happens when methanol is treated with potassium hydroxide.

A) CH₃OH+KOH→CH₃OK+H₂O
B) CH₃OH+KOH →KCH₃O+H₂O
C) CH₃OH+KOH→CH₃OH₂K+H₂O
D) CH₃OH+2KOH→K₂CH₃O₂+2H₂O

Answer 1

When methanol (CH₃OH) is treated with potassium hydroxide (KOH), it forms potassium methoxide (CH₃OK) and water (H₂O).

Step-by-step explanation:

The correct answer is:

A) CH₃OH+KOH→CH₃OK+H₂O

When methanol (CH₃OH) is treated with potassium hydroxide (KOH), it forms potassium methoxide (CH₃OK) and water (H₂O). This reaction is an example of a neutralization reaction between an acid (methanol) and a base (potassium hydroxide).

Overall, the reaction can be written as:

CH₃OH + KOH → CH₃OK + H₂O