Question

Lenox ironed 1/4 of the shirts over the weekend. She plans to split the remainder of the work equally over the next 5 evenings.

1. What fraction of the shirts will Lenox iron each day after school

2. If lenox has 40 shirts, how many shirts will she need to irok on Thursday and friday?

Find its simplest fraction form​

Answer 1

(1)
`Each\ day = (3)/(20)`

(2) 12 offices

Explanation:

Given

`Weekend =(1)/(4)`

First, we need to get the fraction of the rest.

`The\ Rest = 1 - Weekend`

`The\ Rest = 1 - (1)/(4)`

`The\ Rest = (4-1)/(4)`

`The\ Rest = (3)/(4)`

Solving (a): Fraction of each day.

To do this, we simply divide the fraction of the rest by number of days.

`Each\ day = The\ Rest/5`

`Each\ day = (3)/(4)/5`

`Each\ day = (3)/(4)*(1)/(5)`

`Each\ day = (3)/(20)`

Solving (b): Thursday

`Shirts = 40`

First, calculate the fraction of both days.

`Both = (3)/(20)+(3)/(20)`

`Both = (6)/(20)`

`Both = (3)/(10)`

So, the number of shirts to iron on these days is"

`Both = (3)/(10) * 40`

`Both = (120)/(10)`

`Both = 12`