Curium-245 absorbs a neutron, decays through cerium-142, and transmutes into molybdenum-103, releasing 3 neutrons.
The image you sent me shows a nuclear transmutation equation. A curium-245 nucleus is hit with a neutron and changes into molybdenum-103, releasing three neutrons in the process.
The equation is as follows:
245Cm + 1n -> 103Mo + 3n
Here's a breakdown of the equation:
* 245Cm: This represents the curium-245 nucleus, which has 96 protons and 149 neutrons.
* 1n: This represents the neutron that hits the curium-245 nucleus.
* 103Mo: This represents the molybdenum-103 nucleus, which has 42 protons and 61 neutrons.
* 3n: This represents the three neutrons that are released in the process.
The equation is balanced because the total number of protons and neutrons is the same on both sides.
Here are the three tiles that you need to place on the equation:
* Ce: This element should be placed above the arrow on the left side of the equation. It represents cerium, which is an intermediate element that is formed when the curium-245 nucleus absorbs the neutron.
* 142: This number should be placed to the right of Ce. It represents the mass number of the cerium nucleus.
* Xe: This element should be placed above the arrow on the right side of the equation. It represents xenon, which is another intermediate element that is formed when the cerium nucleus decays.
Once you have placed these tiles in the correct locations, the equation will be complete.