Final answer:
The value of n(A⋃B) is the sum of the elements exclusively in set A, exclusively in set B, and those in both sets, which is 15. This corresponds to option B.
Step-by-step explanation:
To find the value of n(A⋃B), which represents the number of elements in the union of set A and set B, we need to add the number of elements that are exclusively in set A, exclusively in set B, and those that are in both sets without counting any element more than once.
Given:
n(A ∩ Bc) = 5 (Elements in A but not in B)
n(B ∩ Ac) = 6 (Elements in B but not in A)
n(A∩B) = 4 (Elements in both A and B)
To find n(A⋃B), we simply add these values together:
n(A⋃B) = n(A ∩ Bc) + n(B ∩ Ac) + n(A∩B)
= 5 + 6 + 4
= 15
Therefore, the value of n(A⋃B) is 15, which corresponds to option B.