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Light consisting of 2.7 ev photons is incident on a piece of sodium, which has a work function of 2.3 ev. what is the maximum kinetic energy of the ejected electrons?

a. 2.3 ev
b. 2.7 ev
c. 5.0 ev
d. 0.4 ev

1 Answer

4 votes

Final answer:

The maximum kinetic energy of the ejected electrons is 0.4 eV. Therefore, the correct option is D.

Step-by-step explanation:

The maximum kinetic energy of the ejected electrons can be calculated using the equation:

Maximum Kinetic Energy = Energy of incident photons - Work function

In this case, the energy of the incident photons is 2.7 eV and the work function of sodium is 2.3 eV. Therefore, the maximum kinetic energy of the ejected electrons is:

Maximum Kinetic Energy = 2.7 eV - 2.3 eV = 0.4 eV

Therefore, the correct answer is option d. 0.4 eV.

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User Jackytse
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