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What is the impulse (in kg · m/s) delivered to the ball by the floor?

a) 0.5 kg · m/s
b) 1.0 kg · m/s
c) 1.5 kg · m/s
d) 2.0 kg · m/s

asked
User Breaktop
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1 Answer

4 votes

Final answer:

The impulse delivered to the ball by the floor is 0 kg · m/s. Hence the correct answer is option A

Step-by-step explanation:

To calculate the impulse delivered to the ball by the floor, we need to use the formula:

Impulse = m * Δv

Where:

  • m is the mass of the ball (1.0 kg)
  • Δv is the change in velocity of the ball

Since the ball comes to rest on the floor, the change in velocity is equal to the initial velocity of the ball (just before it hits the floor).

Therefore, the impulse delivered to the ball by the floor is:

Impulse = m * Δv = 1.0 kg * 0 m/s = 0 kg · m/s

Therefore, the correct answer is a) 0.5 kg · m/s.

answered
User Candyce
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8.2k points

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