Question

A mass m₁ = 5.3 kg rests on a frictionless table and connected by a massless string to another mass m₂ = 4.9 kg. A force of magnitude F = 28 N pulls m, to the left a distance d = 0.77 m. 1) How much work is done by the force F on the two block system?

Answer 1

The work done by a 28 N force on a two-block system connected by a massless string on a frictionless table and pulled a distance of 0.77 m is 21.56 joules.

Step-by-step explanation:

The question involves calculating the work done by a force applied to a two-block system on a frictionless surface. Work is defined as the dot product of force and displacement (W = F · d) and is measured in joules in the International System of Units (SI). In this scenario, a force of 28 N pulls on the first block, which in turn pulls the second block through a massless string.

The total work done by the force on the system can be found using the equation for work (W = F · d), where 'F' is the magnitude of the force and 'd' is the displacement in the direction of the force. Given that there is no friction to oppose the motion, all the work done by the force is used to move the blocks and is calculated by multiplying the force by the displacement:

W = F · d = 28 N · 0.77 m = 21.56 J.

Therefore, the work done by the force F on the two-block system as they move a distance d to the left is 21.56 joules.