asked 138k views
3 votes
It is given that P = (Consonant letters in the word KEJAYAAN) and Q = {x: x is a multiple of 3, and 1≤x≤ 20}. Find n(P) + n(Q).

A 6
B 10
C 12
D 14​

1 Answer

3 votes

The n(P) + n(Q) is B 10 . Therefore , B 10 is correct.

Let's break down the problem step by step.

First, we need to find the set P, which represents the consonant letters in the word "KEJAYAAN."

The word "KEJAYAAN" has the following consonant letters: K, J, Y, N. Therefore, P={K,J,Y,N}.

Now, let's find the set Q, which consists of multiples of 3 within the range 1 to 20. The multiples of 3 in this range are 3, 6, 9, 12, 15, and 18. Therefore, Q={3,6,9,12,15,18}.

Next, we need to find n(P) and n(Q), which represent the number of elements in sets P and Q, respectively.

n(P)=4 (as there are four elements in set P: K, J, Y, N).

n(Q)=6 (as there are six elements in set Q: 3, 6, 9, 12, 15, 18).

Finally, we need to find

n(P)+n(Q):

n(P)+n(Q)=4+6=10

So, the correct answer is B. 10.

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